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Section 1.16 Sweet 16
Subsection 1.16.1 Recommended Tutorials
Before starting on these exercises, you should familiarize yourself with the material covered in the following tutorials:
Subsection 1.16.2 Introduction
We all know that \(16\) exhibits the following interesting property:
\begin{equation*}
16 = 2^4 = 4^2.
\end{equation*}
In this activity, you will explore whether there exist any other positive integers \(a\) and \(b\) (\(a \not = b\) ) such that
\begin{align}
a^b \amp = b^a\text{.}\tag{1.5}
\end{align}
To determine if there are integer solutions to equation
(1.5) , you will need to rely on unusual tactics, including the use of Rolleβs Theorem:
Theorem 1.8 . Rolleβs Theorem.
Let \(f\) be a function that satisfies the following three hypotheses:
\(f\) is continuous on the closed interval \([a,b]\text{.}\)
\(f\) is differentiable on the open interval \((a,b)\text{.}\)
\(f(a) = f(b)\text{.}\)
Then there is a number \(c\) in \((a,b)\) such that \(f'(c) = 0\text{.}\)
Aside If we remove the restriction that
\(a\) and
\(b\) have to be integers, then this problem becomes a lot more interesting.
It can be shown that for any value \(N > { e}^{ e}\text{,}\) there exist real numbers \(a\) and \(b\) that satisfy \(N = a^b = b^a\) with \(a \neq b\text{.}\) To prove this, one needs to be very careful in evaluating the limit
\begin{equation*}
\lim_{\substack{a \rightarrow 1\\ b \rightarrow \infty} } a^b\text{.}
\end{equation*}
It is not obvious that this limit goes to infinity. However, if it does, all \(N > { e}^{ e}\) will have the desired property. It may help to recall that
\begin{equation*}
\lim_{n \rightarrow \infty} \left(1 + \frac{1}{n} \right)^n = { e}\text{.}
\end{equation*}
So, just because the base tends to \(1\) and the exponent tends to infinity, the value of \(a^b\) is not necessarily infinity.
Exercises 1.16.3 Exercises
1.
If you rearrange equation
(1.5) to separate variables, you can write the equation as
\begin{equation*}
\frac{\ln(a)}{a} = \frac{\ln(b)}{b}\text{.}
\end{equation*}
You can obtain this equivalent equation by taking the natural logarithm of both sides of equation
(1.5) . Then, divide that result by both
\(a\) and
\(b\text{.}\) Notice how the equation in this form is set up so that you can apply Rolleβs Theorem.
(a)
Assign the function
\(f(x) = \frac{\ln(x)}{x}\) in Maple.
(b)
Evaluate the derivative of
\(f(x)\text{.}\) Notice that
\(f\) is differentiable (and therefore continuous) for all
\(x > 0\text{.}\)
(c)
Solve for any critical value(s) of
\(f(x)\) where
\(f'(x) = 0\text{.}\) How many critical values are there?
2.
Now you are ready to apply Rolleβs Theorem (and a bit of reasoning) to determine if there are any other positive integers
\(a\) and
\(b\) that satisfy equation
(1.5) . There are no calculations to perform in this exercise. Instead, you will need to adequately explain your answers in paragraph form.
Letβs begin by assuming that
\(a \lt b\text{.}\)
(a)
If
\(a\) and
\(b\) satisfy equation
(1.5) , then
\(f(a) = f(b)\text{.}\) From what Rolleβs Theorem states, what does this tell you about the location of a critical value of
\(f(x)\) where
\(f'(x) = 0\text{?}\)
(b)
Since you have already found the critical value(s) of
\(f(x)\text{,}\) can there be any other positive integers
\(a\) and
\(b\) such that
\(f(a) = f(b)\text{?}\)
3.
What have you concluded about the problem? Are there any other positive integers
\(a\) and
\(b\) (
\(a \not = b\) ) that satisfy equation
(1.5) ?